Calxsolver
Subject:  Precalculus

Expand (2x − 1)³

Apply the binomial theorem with a non-unit leading coefficient.

Answer 8x³ − 12x² + 6x − 1

Solution

  1. Binomial (2x − 1)³
  2. Term k = 0 C(3,0)·(2x)³·(-1)⁰ = 8x³
  3. Term k = 1 C(3,1)·(2x)²·(-1)¹ = -12x²
  4. Term k = 2 C(3,2)·(2x)¹·(-1)² = 6x
  5. Term k = 3 C(3,3)·(2x)⁰·(-1)³ = -1
  6. Expansion 8x³ − 12x² + 6x − 1

Try a similar problem yourself

Use the Binomial Expansion to solve a similar problem with your own values.

Open the solver

More Precalculus problems

Expand (x + 1)⁵ Apply the binomial theorem with whole-number exponent 5. Compute the permutations 7P3 Count the number of ordered arrangements of 3 items chosen from 7. Compute the combinations 10C4 Count the number of unordered selections of 4 items from 10. Multiply (3 + 2i)·(1 − i) Use the FOIL method and i² = −1 to multiply two complex numbers. Divide (1 + i) / (1 − i) Multiply numerator and denominator by the conjugate to divide two complex numbers. Divide (x³ − 1) by (x − 1) Polynomial long division reveals x − 1 as a factor of x³ − 1.