Subject:  Calculus

Tangent line to y = x² at x = 2

Find the equation of the tangent line at a given point.

Answer y = 4x − 4

Solution

  1. Function f(x) = x^2
  2. Point of tangency (2, 4)
  3. Slope f'(2) ≈ 4
  4. Point-slope form y − 4 = 4(x − 2)
  5. Slope-intercept form y = 4x − 4

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