Tangent line to y = x² at x = 2
Find the equation of the tangent line at a given point.
Solution
- Function f(x) = x^2
- Point of tangency (2, 4)
- Slope f'(2) ≈ 4
- Point-slope form y − 4 = 4(x − 2)
- Slope-intercept form y = 4x − 4
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