Truth table: (p → q) ↔ (¬q → ¬p)
Build a truth table to verify that a conditional and its contrapositive are equivalent.
Solution
- Expression (p -> q) = (!q -> !p)
- Variables p, q
- Header p | q | (p -> q) = (!q -> !p)
- Row F | F | T
- Row F | T | T
- Row T | F | T
- Row T | T | T
- Classification Tautology — always true.
Try a similar problem yourself
Use the Truth Table Generator to solve a similar problem with your own values.
Open the solver