Subject:  Finite Math

Truth table: (p → q) ↔ (¬q → ¬p)

Build a truth table to verify that a conditional and its contrapositive are equivalent.

Answer Tautology — always true.

Solution

  1. Expression (p -> q) = (!q -> !p)
  2. Variables p, q
  3. Header p | q | (p -> q) = (!q -> !p)
  4. Row F | F | T
  5. Row F | T | T
  6. Row T | F | T
  7. Row T | T | T
  8. Classification Tautology — always true.

Try a similar problem yourself

Use the Truth Table Generator to solve a similar problem with your own values.

Open the solver