Steady state of a two-state Markov chain
Iterate the distribution and solve for the steady-state vector.
Solution
- Transition matrix 2×2 [0.7, 0.3; 0.4, 0.6]
- Initial distribution p₀ = (1, 0)
- Step 1 p1 = (0.7, 0.3)
- Step 2 p2 = (0.61, 0.39)
- Step 3 p3 = (0.583, 0.417)
- Step 4 p4 = (0.5749, 0.4251)
- Step 5 p5 = (0.57247, 0.42753)
- Steady-state distribution π = (0.571429, 0.428571)
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