Solve x² + 4 = 0
Solve a quadratic equation that has complex conjugate roots.
Solution
- Equation 1x² + 0x + 4 = 0
- Vertex (h, k) = (−b/2a, c − b²/4a) = (0, 4)
- Axis of symmetry x = 0
- Discriminant Δ = b² − 4ac = (0)² − 4·1·4 = -16
- Complex roots Δ < 0 → two complex conjugate roots
- x (−b ± √Δ) / 2a = 0 ± 2i
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